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		<title>Inverse Variation</title>
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					<td align="left" valign="top" bgcolor="#fdf9f1">
					<H1>Inverse Variation</H1>
                                                <hr>
</hr>
                                                <h2><a name="1">Introduction</a></h2>
<div align="center">
  <center>
  <table border="0" cellspacing="1" id="AutoNumber1" height="55" width="350">
    <tr>
      <th bgcolor="#FFCC99" > # workers  </th>
      <td bgcolor="#FFCC99"  align="center"> 1 </td>
      <td bgcolor="#FFCC99"  align="center"> 2 </td>
      <td bgcolor="#FFCC99"  align="center"> 3 </td>
      <td bgcolor="#FFCC99"  align="center"> 4 </td>
    </tr>
    <tr>
      <th bgcolor="#FFCC99" > Hours to complete a job </th>
      <td bgcolor="#FFCC99"  align="center"> 12 </td>
      <td bgcolor="#FFCC99"  align="center"> 6 </td>
      <td bgcolor="#FFCC99"  align="center"> 4 </td>
      <td bgcolor="#FFCC99"  align="center"> 3 </td>
    </tr>
  </table>
  </center>
</div>

<p ><span style="font-size: 14.0pt">If one worker needs 12 hours to complete a job the above
table shows the relationship between number of workers and the amount of hours to complete the job.
From this table, we can see that the amount of hours necesary to complete the job is equal to 12 divided by the number of worker. <p/><i><b>Conclusion:</b> As the number of workers <b>increases</b>, the number of hours to complete the job <b>decreases</b></i>.</span></p><br/><br/>
<div align="center">
  <center>
  <table border="0" id="AutoNumber1" height="55" width="350">
    <tr>
      <th bgcolor="#FFCC99" height="35" width="189">Speed (mph)</th>
      <td bgcolor="#FFCC99" align="center" height="35" width="38">30 </td>
      <td bgcolor="#FFCC99" align="center" height="35" width="38">40 </td>
      <td bgcolor="#FFCC99" align="center" height="35" width="38">50</td>
      <td bgcolor="#FFCC99" align="center" height="35" width="38">60</td>
    </tr>
    <tr>
      <th bgcolor="#FFCC99" height="35" width="189"> Hours driving </th>
      <td bgcolor="#FFCC99" align="center" height="35" width="38">10</td>
      <td bgcolor="#FFCC99" align="center" height="35" width="38">7.5</td>
      <td bgcolor="#FFCC99" align="center" height="35" width="38">6</td>
      <td bgcolor="#FFCC99" align="center" height="35" width="38">5</td>
    </tr>
  </table>
  </center>
</div>

<p ><span style="font-size: 14.0pt">If Sarah goes from her house to Jane's house, which have a distance of 300 miles between them the 
above table shows the relationship between the speed of the car and the number of hours requaired to drive to Jane's house. ( We assume that the speed is constant).
From this table, we can see that the number of hours is equal to 300 divided by the speed of the car. <p/><i><b>Conclusion:</b> As she <b>increases</b> the speed of her car, the number of hours driving to Jane's house <b>decreases</b></i>.</span></p><br/><br/>
<div align="center">
  <center>
  <table border="0" id="AutoNumber1" height="55" width="350">
    <tr>
      <th bgcolor="#FFCC99" height="34" width="189">total # children</th>
      <td bgcolor="#FFCC99" align="center" height="35" width="41">10</td>
      <td bgcolor="#FFCC99" align="center" height="35" width="41">20</td>
      <td bgcolor="#FFCC99" align="center" height="35" width="41">30</td>
      <td bgcolor="#FFCC99" align="center" height="35" width="41">40 </td>
    </tr>
    <tr>
      <th bgcolor="#FFCC99" height="35" width="189"># cookies to each child</th>
      <td bgcolor="#FFCC99" align="center" height="35" width="41">12 </td>
      <td bgcolor="#FFCC99" align="center" height="35" width="41">6</td>
      <td bgcolor="#FFCC99" align="center" height="35" width="41">4</td>
      <td bgcolor="#FFCC99" align="center" height="35" width="41">3</td>
    </tr>
  </table>
  </center>
</div>

<p ><span style="font-size: 14.0pt">In a birthday party there are 120 cookies to distribute them equitably to the children, the 
above table shows the relationship between the total number of children and the number of cookies corresponding to each child.
From this table, we can see that the number of cookies corresponding to each child is equal to 120 divided by the total number of children in the party. <p/><i><b>Conclusion:</b> As the total number of children <b>increases</b>, the number of cookies corresponding to each child  <b>decreases</b>.</i> </span></p><br/><br/>

<p ><span style="font-size: 14.0pt">In all of these relations, one variable is equal to a non-zero constantan divided by other variable.  Such relations are referred to as <b><i>inverse proportions</i></b> or <b><i>inverse variations.</i></b></span></p>
 <br/>
                                                <hr>
</hr>
                                               <h2><a name="2">Definition</a></h2>
<p ><span style="font-size: 14.0pt">Given two variables <b><i>x</i></b> and <b><i>y</i></b>, the statements

<ul><b><i>y </i></b><i>varies inversely as </i> <b><i>x</i></b>,</ul>
<ul><b><i>y </i></b><i>is inversely proportional to </i><b><i>x</i>.</b> </ul>

all mean that <b><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow><mi>y</mi><mo>=</mo><mfrac><mi>k</mi><mi>x</mi></mfrac></mrow></math></b>, for some fixed nonzero real 
number <b><i>k</i></b>. The constant <b><i>k </i></b>is called the <i>constant of variation </i> or <i>constant of proportionality</i>.</span></p>
					
<hr>						
</hr>
<h2><a name="3">Finding the  Formula for Inverse Variation Relations</a></h2>
<p ><font size="4">Inverse variation relations have the form <b><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow><mi>y</mi><mo>=</mo><mfrac><mi>k</mi><mi>x</mi></mfrac></mrow></math></b> where <i><b>x</b></i> and <i><b>y</b></i> are variables and <b><i>k</i></b> is a non-zero constant. This is a relationship between two variables in which the product is a constant.
 The formula for an inverse variation 
relationship can be found with the following steps.</font></p>

<table border="1" id="AutoNumber1" style="border-width: 0">
  						<tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99">
    							<p ><b><i>
                                <span style="font-size: 14.0pt">Step 1:</span></i></b><span style="font-size: 14.0pt"> </span>
                                <span style="font-size: 14pt"> <i> Translate the 
                                statement into a inverse variation formula.</i></span></p>
    							<p  align="center"> <b><i>
                                <font style="font-size: 14pt">y </font> </i></b>
                                <font style="font-size: 14pt">is inversely proportional to</font><i><b><font style="font-size: 14pt"> 
                                x </font></b><font style="font-size: 14pt">means</font></i></p>
                                <p  align="center" style="text-align:center">
                                <b><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow><mi>y</mi><mo>=</mo><mfrac><mi>k</mi><mi>x</mi></mfrac></mrow></math></b></p>
                                <p/></td>
  						</tr>
  						<tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99">
    							<b><i><span style="font-size: 14.0pt">Step 2:</span></i></b><span style="font-size: 14.0pt"> 
                                <i> Substitute  known values to find </i><i>k.</i></span><p/></td>
  						</tr>
  						<tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99">
    							<b><i><span style="font-size: 14.0pt">Step 3:</span></i></b><span style="font-size: 14.0pt"> </span>
                                <span style="font-size: 14pt"> <i> Substitute k  
                                 and write the formula.</i></span><p/><p/>
                                <p/><p/><p/><p/><p/></td>
  						</tr>
						</table><br/>
<h2 style="margin-left: 55">Examples </h2>
<h3 style="margin-left: 55">Example 1</h3>
<p  style="margin-left: 55"><span style="font-size: 14pt"><b>
<i> </i></b></span><span style="font-size: 14.0pt"><b><i>r</i></b> is inversely proportional to<i><b> 
s</b></i>. If <b><i>r </i></b>= 15 when <b><i>s </i></b>= 3,</span><span style="FONT-SIZE: 14pt"> then write the formula for the relation between <i><b>r</b></i> and <b><i>s</i></b>.</span></p>

<table border="1" id="AutoNumber3" style="border-width: 0; margin-left: 55">
  						<tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99">
    							<p  style="margin-left: 25"><b><i>
                                <span style="font-size: 14.0pt">Step 1:</span></i></b><span style="font-size: 14.0pt"> </span>
                                <span style="font-size: 14pt"> <i> Translate the 
                                statement into a inverse variation formula.</i></span></p>
    							<p  align="center">
                                <span style="font-size: 14pt"><b><i>r </i></b></span><b><i><font style="font-size: 14pt">
                                </font> </i></b><span style="font-size: 14.0pt">is inversely proportional to</span><i><b><font style="font-size: 14pt"> 
                                s </font></b><font style="font-size: 14pt">means</font></i></p>
                                <p  align="center" style="text-align:center; margin-left:15">
                                <b><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow><mi>r</mi><mo>=</mo><mfrac><mi>k</mi><mi>s</mi></mfrac></mrow></math></b></p>
                                <p style="margin-left: 25"/></td>
  						</tr>
  						<tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99">
    							<p  style="margin-left: 25"><b><i>
                                <span style="font-size: 14.0pt">Step 2:</span></i></b><span style="font-size: 14.0pt"> 
                                <i> Substitute  known values to find </i><i>k.</i></span></p>
                                <p  align="center" style="text-align:center; margin-left:15">
                                <b><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow><mi>15</mi><mo>=</mo><mfrac><mi>k</mi><mi>3</mi></mfrac></mrow></math></b></p>
                                <p  align="center" style="text-align:center; margin-left:15">
                                <i>
                                <span style="font-size: 14.0pt"><b><i>k </i></b>=15 &#x00B7; 3 = 45</span></i></p>
                                
                                <p></p>
                                <p style="margin-left: 25"/></td>
  						</tr>
  						<tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99">
    							<p  style="margin-left: 25"><b><i>
                                <span style="font-size: 14.0pt">Step 3:</span></i></b><span style="font-size: 14.0pt"> </span>
                                <span style="font-size: 14pt"> <i> Substitute k 
                                 and write the formula.</i> </span></p>
                                <p  align="center" style="text-align:center; margin-left:15">
                                <b><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow><mi>r</mi><mo>=</mo><mfrac><mi>45</mi><mi>s</mi></mfrac></mrow></math></b></p>
                                
                                <p style="margin-left: 25"/></td>
  						</tr>
						</table><br/>	
<p style="margin-left: 55" ><font size="4"><i><b>Conclusion:</b></i> 
the formula to express the relationship between <b><i>r </i></b>and <b><i>s </i>
</b>is </font>
                               <b><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow><mi>r</mi><mo>=</mo><mfrac><mi>45</mi><mi>s</mi></mfrac></mrow></math></b></p>
<br/>

<h3 style="margin-left: 55">Example 2</h3>
<p  style="margin-left: 55"><b><i><span style="font-size: 14.0pt">c</span></i></b><span style="font-size: 14.0pt"> 
varies inversely as <b><i>d</i></b>. If <b><i>c </i></b>= 100 when <b><i>d </i>
</b>= 0.2, </span><span style="FONT-SIZE: 14pt">then write the formula for the
relation between <b><i>c </i></b> and <b><i>d</i></b>.</span></p>

<p  style="margin-left: 25"></p>

<table border="1" id="AutoNumber2" style="border-width: 0; margin-left: 55">
  						<tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99">
    							<p  style="margin-left: 25"><b><i>
                                <span style="font-size: 14.0pt">Step 1:</span></i></b><span style="font-size: 14.0pt"> </span>
                                <span style="font-size: 14pt"> <i> Translate the 
                                statement into a inverse variation formula.</i></span></p>
    							<p  align="center">
                                <span style="font-size: 14pt"><b><i>c</i></b></span><b><i><font style="font-size: 14pt">
                                </font> </i></b><span style="font-size: 14.0pt"> varies inversely as</span><i><b><font style="font-size: 14pt"> d </font></b><font style="font-size: 14pt">
                                means</font></i></p>
                                <p  align="center" style="text-align:center; margin-left:15">
                                <b><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow><mi>c</mi><mo>=</mo><mfrac><mi>k</mi><mi>d</mi></mfrac></mrow></math></b></p>
                                
                                <p style="margin-left: 25"/></td>
  						</tr>
  						<tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99">
    							<p  style="margin-left: 25"><b><i>
                                <span style="font-size: 14.0pt">Step 2:</span></i></b><span style="font-size: 14.0pt"> 
                                <i> Substitute  known values to find </i><i>k.</i></span></p>
                                <p  align="center" style="text-align:center; margin-left:15">
                                <b><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow><mi>100</mi><mo>=</mo><mfrac><mi>k</mi><mi>0.2</mi></mfrac></mrow></math></b></p>

                                <p  align="center" style="text-align:center; margin-left:15">
                                <i>
                                <span style="font-size: 14.0pt"><b><i>k </i></b>=100 &#x00B7; 0.2=20</span></i></p>
                                
                                <p style="margin-left: 25"/></td>
  						</tr>
  						<tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99">
    							<p  style="margin-left: 25"><b><i>
                                <span style="font-size: 14.0pt">Step 3:</span></i></b><span style="font-size: 14.0pt"> </span>
                                <span style="font-size: 14pt"> <i> Substitute k  
                                 and write the formula.</i> </span></p>
                                <p  align="center" style="text-align:center; margin-left:15">
                                <b><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow><mi>c</mi><mo>=</mo><mfrac><mi>20</mi><mi>d</mi></mfrac></mrow></math></b></p>
                                
                                <p style="margin-left: 25"/></td>
  						</tr>
						</table><br/>
<p style="margin-left: 55" ><font size="4"><b><i>Conclusion:</i></b> 
the formula to express the relationship between </font>
                                <span style="font-size: 14.0pt"><b><i>c</i></b></span><font size="4"><b><i>
</i></b> and </font>
                                <span style="font-size: 14.0pt"><i><b>d</b></i></span><font size="4"><b><i>
</i></b> is </font>
                               <p style="margin-left: 55"> <b><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow><mi>c</mi><mo>=</mo><mfrac><mi>20</mi><mi>d</mi></mfrac></mrow></math></b></p>
                               </p><br/>
<center><img src="../practice_image.jpg" onClick ="tut('REVIEW/InverseVariation/inverseVar_form.db','4',500,650)"></img></center>
<br/>

<hr>
</hr>	
						<h2><a name="4">Steps to Solve Simple Inverse Variation Problems</a></h2>
<p ><font size="4">Simple inverse variation problems consist in 
find a formula and verify what happen with a quantity when we change the other 
quantity of 
the problem.</font></p>

<table border="1" id="AutoNumber1" style="border-width: 0">
  						<tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99">
    							<p ><b><i>
                                <span style="font-size: 14.0pt">Step 1:</span></i></b><span style="font-size: 14.0pt"> 
                                <i> Find formula.</i></span></p></td>
                                
  						</tr>
  						<tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99">
    							<b><i><span style="font-size: 14.0pt">Step 2:</span></i></b><span style="font-size: 14.0pt"> 
                                <i> Identify known variables and substitute into 
                                formula.</i></span><p/></td>
  						</tr>
  						<tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99">
    							<span style="font-size: 14.0pt">
    							<b><i>Step 3: </i></b> <i> Solve for Unknown.</i> </span><p/></td>
  						</tr>
  						</table>	
<h2 style="margin-left: 55">Examples </h2>
<h3 style="margin-left: 55">Example 1</h3>
<p  style="margin-left: 55"><span style="font-size: 14.0pt"><b>
<i>f  </i></b> </span><font size="4"> is inversely proportional to</font><span style="font-size: 14.0pt">
<b><i> g</i></b>. If <b><i>f </i></b>= 5 when <b><i>g </i></b>= 25, then find the value of <b><i>g</i></b><i><b></b> </i> when </span></p><p  style="margin-left: 55"><span style="font-size: 14.0pt"><i><b> f </b></i>= 15.</span></p>
<p  style="margin-left: 55"/>


<table border="1" id="AutoNumber4" style="border-width: 0; margin-left: 55">
  						<tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99" rowspan="3">
    							<p  style="margin-left: 25"><b><i>
                                <span style="font-size: 14.0pt">Step 1:</span></i></b><span style="font-size: 14.0pt"> 
                                <p/><i> Find formula</i></span></p>
                                <p style="margin-left: 25"/></td>
    					
				<td style="border-style: none; border-width: medium" bgcolor="#FFCC99">
    							<p  style="margin-left: 25"><b><i>
                                <span style="font-size: 14.0pt"> 1:</span></i></b><span style="font-size: 14.0pt"> </span>
                                <span style="font-size: 14pt"> <i> Translate the 
                                statement into a inverse variation formula.</i></span></p>
    							<p  align="center">
                                <span style="font-size: 14pt"><b><i>f</i></b></span><b><i><font style="font-size: 14pt">
                                </font> </i></b><span style="font-size: 14.0pt"> is inversely proportional to </span><i><b><font style="font-size: 14pt"> g </font></b><font style="font-size: 14pt">
                                means</font></i></p>
                                <p  align="center" style="text-align:center; margin-left:15">
                                <b><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow><mi>f</mi><mo>=</mo><mfrac><mi>k</mi><mi>g</mi></mfrac></mrow></math></b></p>
                                
                                <p style="margin-left: 25"/></td>
  						</tr>
  						<tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99">
    							<p  style="margin-left: 25"><b><i>
                                <span style="font-size: 14.0pt"> 2:</span></i></b><span style="font-size: 14.0pt"> 
                                <i> Substitute  known values to find </i><i>k.</i></span></p>
                                <p  align="center" style="text-align:center; margin-left:15">
                                <b><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow><mi>5</mi><mo>=</mo><mfrac><mi>k</mi><mi>25</mi></mfrac></mrow></math></b></p>

                                <p  align="center" style="text-align:center; margin-left:15">
                                <i>
                                <span style="font-size: 14.0pt"><b><i>k </i></b>=5 &#x00B7; 25 = 125</span></i></p>
                                
                                <p style="margin-left: 25"/></td>
				   </tr>
                                   <tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99">
    							<p  style="margin-left: 25"><b><i>
                                <span style="font-size: 14.0pt"> 3:</span></i></b><span style="font-size: 14.0pt"> </span>
                                <span style="font-size: 14pt"> <i> Substitute k  
                                 and write the formula.</i></span></p>
                                <p  align="center" style="text-align:center; margin-left:15">
                                <b><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow><mi>f</mi><mo>=</mo><mfrac><mi>125</mi><mi>g</mi></mfrac></mrow></math></b></p>
                                
                                <p style="margin-left: 25"/></td>
  						</tr>
  						<tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99" colspan="2">
    							<p  style="margin-left: 25"><b><i>
                                <span style="font-size: 14.0pt">Step 2:</span></i></b><span style="font-size: 14.0pt"> 
                                <i> Identify known variables and substitute into 
                                formula.</i></span></p>
                                <p  align="center" style="text-align:center; margin-left:15">
             			<b><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow><mi>10</mi><mo>=</mo><mfrac><mi>125</mi><mi>g</mi></mfrac></mrow></math></b></p>
                                <p style="margin-left: 25"/></td>
  						</tr>
  						<tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99" colspan="2">
    							<p  style="margin-left: 25"><b><i>
                                <span style="font-size: 14.0pt">Step 3:</span></i></b><span style="font-size: 14.0pt"> </span>
                                <span style="font-size: 14pt"> <i> Solve for Unknown.</i></span></p>
                                <p align="center">
                                <i>
                                <span style="font-size: 14.0pt"><b><i>g </i></b>= 12.5</span>
                                </i> </p>
                                
                                <p style="margin-left: 25"/></td>
  						</tr>
  						</table>	
<p  style="margin-left: 55"><font size="4"><b><i>Conclusion:</i></b> <b><i> g = </i></b>
12.5 when <b><i>f</i></b> = 10.</font></p><br/>


<h3 style="margin-left: 55">Example 2</h3>
<p  style="margin-left: 55"><font style="font-size: 14pt"><b>
<i>t </i></b></font><font size="4">varies inversely as </font><span style="font-size: 14.0pt">
<b><i>q</i></b>. If <b><i>t </i></b>= 240 when <b><i>q </i></b>= 0.01, then find the value of <i><b>t
</b> </i>when<i><b> q </b></i>= 8 </span></p>



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  						<tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99" rowspan="3">
    							<p  style="margin-left: 25"><b><i>
                                <span style="font-size: 14.0pt">Step 1:</span></i></b><span style="font-size: 14.0pt"> 
                                <p/><i> Find formula</i></span></p>
                                <p style="margin-left: 25"/></td>
    					
				<td style="border-style: none; border-width: medium" bgcolor="#FFCC99">
    							<p  style="margin-left: 25"><b><i>
                                <span style="font-size: 14.0pt"> 1:</span></i></b><span style="font-size: 14.0pt"> </span>
                                <span style="font-size: 14pt"> <i> Translate the 
                                statement into a inverse variation formula.</i></span></p>
    							<p  align="center">
                                <span style="font-size: 14pt"><b><i>t</i></b></span><b><i><font style="font-size: 14pt">
                                </font> </i></b><span style="font-size: 14.0pt"> varies inversely as </span><i><b><font style="font-size: 14pt"> q </font></b><font style="font-size: 14pt">
                                means</font></i></p>
                                <p  align="center" style="text-align:center; margin-left:15">
                                <b><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow><mi>t</mi><mo>=</mo><mfrac><mi>k</mi><mi>q</mi></mfrac></mrow></math></b></p>
                                
                                <p style="margin-left: 25"/></td>
  						</tr>
  						<tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99">
    							<p  style="margin-left: 25"><b><i>
                                <span style="font-size: 14.0pt"> 2:</span></i></b><span style="font-size: 14.0pt"> 
                                <i> Substitute  known values to find </i><i>k.</i></span></p>
                                <p  align="center" style="text-align:center; margin-left:15">
                                <b><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow><mi>240</mi><mo>=</mo><mfrac><mi>k</mi><mi>0.01</mi></mfrac></mrow></math></b></p>

                                <p  align="center" style="text-align:center; margin-left:15">
                                <i>
                                <span style="font-size: 14.0pt"><b><i>k </i></b>=240 &#x00B7; 0.01 = 2.4</span></i></p>
                                
                                <p style="margin-left: 25"/></td>
				   </tr>
                                   <tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99">
    							<p  style="margin-left: 25"><b><i>
                                <span style="font-size: 14.0pt"> 3:</span></i></b><span style="font-size: 14.0pt"> </span>
                                <span style="font-size: 14pt"> <i> Substitute </i> <i>k</i>  
                                 and write the formula.</span></p>
                                <p  align="center" style="text-align:center; margin-left:15">
                                <b><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow><mi>t</mi><mo>=</mo><mfrac><mi>2.4</mi><mi>q</mi></mfrac></mrow></math></b></p>
                                
                                <p style="margin-left: 25"/></td>
  						</tr>
  						<tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99" colspan="2">
    							<p  style="margin-left: 25"><b><i>
                                <span style="font-size: 14.0pt">Step 2:</span></i></b><span style="font-size: 14.0pt"> 
                                <i> Identify known variables and substitute into 
                                formula.</i></span></p>
                                <p  align="center" style="text-align:center; margin-left:15">
             			<b><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow><mi>t</mi><mo>=</mo><mfrac><mi>2.4</mi><mi>8</mi></mfrac></mrow></math></b></p>
                                <p style="margin-left: 25"/></td>
  						</tr>
  						<tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99" colspan="2">
    							<p  style="margin-left: 25"><b><i>
                                <span style="font-size: 14.0pt">Step 3:</span></i></b><span style="font-size: 14.0pt"> </span>
                                <span style="font-size: 14pt"> <i> Solve for Unknown.</i></span></p>
                                <p align="center">
                                <i>
                                <span style="font-size: 14.0pt"><b><i>t </i></b>= 0.3</span>
                                </i> </p>
                                
                                <p style="margin-left: 25"/></td>
  						</tr>
  						</table><br/>
<p  style="margin-left: 55"><font size="4"><b><i>Conclusion:</i></b>
<b><i> t = </i></b>0.3<b><i> </i></b> when <b><i>q</i></b> = 8</font></p><br/>
<center><img src="../practice_image.jpg" onClick ="tut('REVIEW/InverseVariation/inverseVar_simpExpr.db','8',500,650)"></img></center>
<br/>
<p  style="margin-left: 55"/>
<h2><a name="5">Steps to Solve Word problems of Inverse Variation</a></h2>
<p><font size="4">Word problems of inverse variation are problems where the 
involved quantities have names, but the way to solve them is not different from 
the last section. The steps to solve then are the same</font></p>

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  						<tr>
    							<td style="border-style: none; border-width: medium; margin-left:55" bgcolor="#FFCC99">
    							<p ><b><i>
                                <span style="font-size: 14.0pt">Step 1:</span></i></b><span style="font-size: 14.0pt">
                                <i> Find formula.</i></span></p></td>
                                
  						</tr>
  						<tr>
    							<td style="border-style: none; border-width: medium; margin-left:55" bgcolor="#FFCC99">
    							<b><i><span style="font-size: 14.0pt">Step 2:</span></i></b><span style="font-size: 14.0pt">
                                <i> Identify known variables and substitute into 
                                formula.</i></span><p/></td>
  						</tr>
  						<tr>
    							<td style="border-style: none; border-width: medium; margin-left:55" bgcolor="#FFCC99">
    							<span style="font-size: 14.0pt">
    							<b><i>Step 3: </i></b><i>Solve for Unknown</i></span><p/></td>
  						</tr>
  						</table>	
<h2 style="margin-left: 55">Examples</h2>
<h3 style="margin-left: 55">Example 1</h3>
<p  style="margin-left: 55"><font size="4">Let a rectangle which its area does not change. The length of a rectangle varies inversely as the width.  If the length of a rectangle is 20 ft when the width is 8 ft, find the length of the rectangle when the width is 10 ft.?</font></p>
<p  style="margin-left: 55"/>



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  						<tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99" rowspan="3">
    							<p  style="margin-left: 25"><b><i>
                                <span style="font-size: 14.0pt">Step 1:</span></i></b><span style="font-size: 14.0pt">
                                <i> Find formula</i></span></p>
                                <p style="margin-left: 55"/></td>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99">
    							<p  style="margin-left: 25"><b><i>
                                <font size="3">1:</font></i></b><font size="3"> </font>
                                <i>
                                <font size="4"> Translate the 
                                statement into a inverse variation formula.</font></i></p>
    							<p align="center">
                                <font size="4">The <i><b>length</b></i> of a rectangle varies inversely as the <i><b>width</b></i> </font><i><b><font size="4"> </font></b>
                                <font size="4"> means</font></i></p>
    							<p  align="center">
                                <b><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow><mi>length</mi><mo>=</mo><mfrac><mi>k</mi><mi>width</mi></mfrac></mrow></math></b></p>
                                <p/></td>
  						</tr>
  						<tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99">
    							<p  style="margin-left: 25"><b><i>
                                <span style="font-size: 14.0pt"> 2:</span></i></b><span style="font-size: 14.0pt"> 
                                <i> Substitute  known values to find </i><i>k.</i></span></p>
                                <p  align="center" style="text-align:center; margin-left:15">
                                <b><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow><mi>20</mi><mo>=</mo><mfrac><mi>k</mi><mi>8</mi></mfrac></mrow></math></b></p>

                                <p  align="center" style="text-align:center; margin-left:15">
                                <i>
                                <span style="font-size: 14.0pt"><b><i>k </i></b>=20 &#x00B7; 8 = 160</span></i></p>
                                
                                <p style="margin-left: 25"/></td>
				   </tr>
                                   <tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99">
    							<p  style="margin-left: 25"><b><i>
                                <span style="font-size: 14.0pt"> 3:</span></i></b><span style="font-size: 14.0pt"> </span>
                                <span style="font-size: 14pt"> <i> Substitute k  
                                 and write the formula.</i></span></p>
                                <p  align="center" style="text-align:center; margin-left:15">
                                <b><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow><mi>length</mi><mo>=</mo><mfrac><mi>160</mi><mi>width</mi></mfrac></mrow></math></b></p>
                                
                                <p style="margin-left: 25"/></td>
  						</tr>
  						<tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99" colspan="2">
    							<p  style="margin-left: 25"><b><i>
                                <span style="font-size: 14.0pt">Step 2:</span></i></b><span style="font-size: 14.0pt"> 
                                <i> Identify known variables and substitute into 
                                formula.</i></span></p>
                                <p  align="center" style="text-align:center; margin-left:15">
             			<b><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow><mi>lenght</mi><mo>=</mo><mfrac><mi>160</mi><mi>10</mi></mfrac></mrow></math></b></p>
                                <p style="margin-left: 25"/></td>
  						</tr>
  						<tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99" colspan="2">
    							<p  style="margin-left: 25"><b><i>
                                <span style="font-size: 14.0pt">Step 3:</span></i></b><span style="font-size: 14.0pt"> </span>
                                <span style="font-size: 14pt"> <i> Solve for Unknown.</i></span></p>
                                <p align="center">
                                <i>
                                <span style="font-size: 14.0pt"><b><i>length </i></b>= 16</span>
                                </i> </p>
                                
                                <p style="margin-left: 25"/></td>
  						</tr>
  						</table><br/>
<p style="margin-left: 55" ><font size="4"><i><b>Conclusion: </b></i>
The length of a rectangle which area is 160 feet square is 16 when its width is 10.</font></p><br/>


<h3 style="margin-left: 55">Example 2</h3>
<p  style="margin-left: 55"><font size="4">The time to complete a project is inversely proportional to number of people who is doing the project. A certain project can be completed by 5 workers in 24 days.  In order to 
     finish the project sooner, the company plans to hire additional workers.  How               
     many workers are needed to finish the project in  15 days?
</font></p>
<p  style="margin-left: 55"/>



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  						<tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99" rowspan="3">
    							<p  style="margin-left: 25"><b><i>
                                <span style="font-size: 14.0pt">Step 1:</span></i></b><span style="font-size: 14.0pt"> 
                                 Find formula</span></p>
                                <p style="margin-left: 55"/></td>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99">
    							<p  style="margin-left: 25"><b><i>
                                <font size="3">1:</font></i></b><font size="3"> </font>
                                <i>
                                <font size="4"> Translate the 
                                statement into a inverse variation formula.</font></i></p>
    							<p  align="center">
                                <font size="4">The <i><b>time</b></i> to do a project is inversely proportional to number of <i><b>worker</b></i> doing the project </font><i>
                                <font size="4">means</font></i></p>
    							<p  align="center">
                                <b><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow><mi>time</mi><mo>=</mo><mfrac><mi>k</mi><mi># workers</mi></mfrac></mrow></math></b></p>
                                <p/></td>
  						</tr>
  						<tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99">
    							<p  style="margin-left: 25"><b><i>
                                <span style="font-size: 14.0pt"> 2:</span></i></b><span style="font-size: 14.0pt"> 
                                <i> Substitute  known values to find </i><i>k.</i></span></p>
                                <p  align="center" style="text-align:center; margin-left:15">
                                <b><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow><mi>24</mi><mo>=</mo><mfrac><mi>k</mi><mi>5</mi></mfrac></mrow></math></b></p>

                                <p  align="center" style="text-align:center; margin-left:15">
                                <i>
                                <span style="font-size: 14.0pt"><b><i>k </i></b>=24 &#x00B7; 5 = 120</span></i></p>
                                
                                <p style="margin-left: 25"/></td>
				   </tr>
                                   <tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99">
    							<p  style="margin-left: 25"><b><i>
                                <span style="font-size: 14.0pt"> 3:</span></i></b><span style="font-size: 14.0pt"> </span>
                                <span style="font-size: 14pt"> <i> Substitute k  
                                 and write the formula.</i></span></p>
                                <p  align="center" style="text-align:center; margin-left:15">
                                <b><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow><mi>time</mi><mo>=</mo><mfrac><mi>120</mi><mi># workers</mi></mfrac></mrow></math></b></p>
                                
                                <p style="margin-left: 25"/></td>
  						</tr>
  						<tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99" colspan="2">
    							<p  style="margin-left: 25"><b><i>
                                <span style="font-size: 14.0pt">Step 2:</span></i></b><span style="font-size: 14.0pt"> 
                                <i> Identify known variables and substitute into 
                                formula.</i></span></p>
                                <p  align="center" style="text-align:center; margin-left:15">
             			<b><math xmlns="http://www.w3.org/1998/Math/MathML"><mrow><mi>15</mi><mo>=</mo><mfrac><mi>120</mi><mi># workers</mi></mfrac></mrow></math></b></p>
                                <p style="margin-left: 25"/></td>
  						</tr>
  						<tr>
    							<td style="border-style: none; border-width: medium" bgcolor="#FFCC99" colspan="2">
    							<p  style="margin-left: 25"><b><i>
                                <span style="font-size: 14.0pt">Step 3:</span></i></b><span style="font-size: 14.0pt"> </span>
                                <span style="font-size: 14pt"> <i> Solve for Unknown.</i></span></p>
                                <p align="center">
                                <i>
                                <span style="font-size: 14.0pt"><b># workers </b>= 8</span>
                                </i> </p>
                                
                                <p style="margin-left: 25"/></td>
  						</tr>
  						</table>	
<br/>
<p style="margin-left: 55"><font size="4"><i><b>Conclusion: </b></i>
The company needs 8 workers to finish the project in 15 days.</font></p><br/>
<center><img src="../practice_image.jpg" onClick ="tut('REVIEW/InverseVariation/InverseVariationOK.db','10',500,650)"></img></center>
<br/>	
	
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